5x^2+3x+2=50

Solution for 5x^2+3x+2=50 equation:

5x^2+3x+2=50

We move all terms to the left:

5x^2+3x+2-(50)=0

We add all the numbers together, and all the variables

5x^2+3x-48=0

a = 5; b = 3; c = -48;
Δ = b2-4ac
Δ = 32-4·5·(-48)
Δ = 969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{969}}{2*5}=\frac{-3-\sqrt{969}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{969}}{2*5}=\frac{-3+\sqrt{969}}{10}
$